Check string ends with semi-colon

Involved Joined: Apr 06, 2008 Posts: 484

I assume I would use reg ex for this but anyway here we go Smile

if my var holds a javascript string (for adding custom code dynamically), how can i check the strings ends with a semi-colon.

example:

Code:







$myVar = 'this.insertBefore( elem, this.firstChild );';

it seems php has not yet built in the function

Code:




$myVar = Check_For_Stupid_SemiColon($myVar);

Posted: Tue Feb 17, 2009 8:34 pm

Code:




if (!preg_match("/;\z/", $myVar)) {


   $string = $myVar . ';';


}

Posted: Tue Feb 17, 2009 8:35 pm

Awesome Tutorial!

http://www.phpro.org/tutorials/Introduction-to-PHP-Regex.html

Posted: Tue Feb 17, 2009 9:31 pm

ok thanks

Posted: Tue Feb 17, 2009 9:32 pm

The code I posted above was a little off.

Code:




if (!preg_match("/;\z/", $myVar)) {


   $myVar = $myVar . ';';


}

Posted: Wed Feb 18, 2009 5:21 am

I just had a thought Sad

I am getting these values from the database and they are inserted via a textarea.If they are entered on a per line basis it should be fine but if not it may cause issue's.

e.g.

Code:




this.insertBefore( elem, this.firstChild );


this.insertBefore( elem, this.firstChild );


this.insertBefore( elem, this.firstChild );


this.insertBefore( elem, this.firstChild );

Code:




this.insertBefore( elem, this.firstChild );this.insertBefore( elem, this.firstChild );this.insertBefore( elem, this.firstChild );this.insertBefore( elem, this.firstChild );

any ideas on that.

registered · Posted: Wed Feb 18, 2009 6:36 am

You almost need a javascript syntax checker (but I don't know of one off the top of my head). There are so many permutations that I am concerned about regex being able to cover them all. But, if there isn't such a thing out there, you may be stuck with writing maybe a series of regex's.

Posted: Wed Feb 18, 2009 3:45 pm

or I could just enter them one per line ROTFL

Posted: Wed Feb 18, 2009 8:57 pm

You just had to ask didn't you... killing me

Posted: Thu Feb 19, 2009 2:17 am

lol